which congruence postulate or theorem can prove that angle ABD = angle CDB?

Given :
[tex]\bar{AB}\cong\bar{CD}[/tex]and
[tex]\bar{BC}\cong\bar{AD}[/tex]Required: Congruency postulate
Explanation: In triangle ABD and triangle CDB
[tex]\bar{AB}\cong\bar{CD}[/tex][tex]\bar{BC}=\bar{AD}[/tex]and
[tex]\bar{BD}=\bar{BD}[/tex]Therefore, by SSS (Side Side Side) congurency theorem
Triangle ABD is congurent to triangle CDB.
Final Answer: Option 2 is correct