Question

I want you to help me.to solve my matrix

Answer 1

We have the following matrix

$\begin{bmatrix}{4} & {3} & {2} \\ {-1} & {4} & {x} \\ {2} & {2} & {3}\end{bmatrix}=17$

We must find the value of "x", for this we will find the total value of the matrix by performing the corresponding multiplications and making the matrix equal to the given value.

$4\cdot(4\cdot3-2x)-3(-1\cdot3-2x)+2(-1\cdot2-2\cdot4)=17$

After we have the equality we clear "x".

$\begin{gathered} \\ 4(12-2x)-3(-3-2x)+2(-2-8)=17 \\ 48-8x+9+6x-20=17 \\ 8x-6x=48+9-20-17 \\ 2x=20 \\ x=\frac{20}{2} \\ x=10 \end{gathered}$

In conclusion, the answer is x=10

$\begin{bmatrix}{a} & {b} & {} \\ {c} & {d} & {} \\ {} & {} & {}\end{bmatrix}=a\cdot b-c\cdot d$$\begin{gathered} \begin{bmatrix}{-1} & {4} & {} \\ {2} & {2} & {} \\ {} & {} & {}\end{bmatrix} \\ (-1\cdot2-4\cdot2)=(-2-8)=-10 \end{gathered}$

First option

$\begin{gathered} 2(-2-8) \\ 2\cdot(-10)=-20 \end{gathered}$

Second option

$\begin{gathered} 2(-2-8) \\ -4-16=-20 \end{gathered}$