1. the sequence is:
500, 250, 125, ...
the common ratio (r) is:
250/500 = 1/2 = 0.5
125/250 = 1/2 = 0.5
So, the sequence is a geometric sequence.
Explicit formula:
[tex]\begin{gathered} a_n=a_1\cdot r^{n\text{ - 1}} \\ a_n=500\cdot0.5^{n\text{ - 1}} \end{gathered}[/tex]Recursive formula:
[tex]\left\{ \begin{aligned}a_1=500 \\ a_n=r\cdot a_{n\text{ - 1}}\end{aligned}\right.[/tex]2. In the formulas, n represents days. Using the explicit formula with an = 1, we get:
[tex]\begin{gathered} 1\text{ = 500}\cdot0.5^{n\text{ - 1}} \\ \frac{1}{500}=0.5^{n\text{ - 1}} \\ ln(\frac{1}{500})\text{ = (n - 1)}\cdot\ln (0.5) \\ \frac{ln(\frac{1}{500})}{ln(0.5)}+1\text{ = n} \\ 9.965=\text{ n} \end{gathered}[/tex]then, after 10 days there will be less than 1 skittle in the bag