Respuesta :

Given an arbitrary line with gradient m, that passes through a point (x1, y1)

The equation of the line is

y - y1 = m( x - x1)

To shift the line up by g units

Then, the new equation becomes

y - y1 + g = m(x - x1)

To shift the line down by g units

Then, the new equation becomes

y - y1 - g = m(x - x1)

Taking the axis of reflection as x = 0

The reflection of the line is

-y - y1 = m( x - x1)

Taking the axis of reflection as y = 0

The reflection of the line is

y - y1 = m( -x - x1)

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