A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 73.9° with the horizontal. The force in each chain is 38.4 N. Determine the mass of the light in kilograms (kg). Use the approximation g ≈ 10 m/s^2.Answer: ___________ kg

Respuesta :

Given:

The is supported by four strong chains which make an angle of

[tex]\theta=73.9\degree[/tex]

The force on each chain is

[tex]F=38.4\text{ N}[/tex]

The acceleration due to gravity is

[tex]g=10\text{ m/s}^2[/tex]

To find:

The mass of the light

Explanation:

The horizontal force by each chain is given by,

[tex]\begin{gathered} F_h=Fcos\theta \\ =38.4\times cos73.9\degree \\ =10.6\text{ N} \end{gathered}[/tex]

The vertical force by each chain is given by,

[tex]\begin{gathered} F_v=Fsin\theta \\ =38.4\times sin73.9\degree \\ =36.9\text{ N} \end{gathered}[/tex]

The weight of the light is balanced by the vertical force of the chains.

The weight of the light is,

[tex]\begin{gathered} W=4F_v \\ =4\times36.9 \\ =147.6\text{ N} \end{gathered}[/tex]

The mass of the light is,

[tex]\begin{gathered} m=\frac{W}{g} \\ =\frac{147.6}{10} \\ =14.76\text{ kg} \end{gathered}[/tex]

Hence, the mass of the light is 14.76 kg.

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