Given:
The is supported by four strong chains which make an angle of
[tex]\theta=73.9\degree[/tex]The force on each chain is
[tex]F=38.4\text{ N}[/tex]The acceleration due to gravity is
[tex]g=10\text{ m/s}^2[/tex]To find:
The mass of the light
Explanation:
The horizontal force by each chain is given by,
[tex]\begin{gathered} F_h=Fcos\theta \\ =38.4\times cos73.9\degree \\ =10.6\text{ N} \end{gathered}[/tex]The vertical force by each chain is given by,
[tex]\begin{gathered} F_v=Fsin\theta \\ =38.4\times sin73.9\degree \\ =36.9\text{ N} \end{gathered}[/tex]The weight of the light is balanced by the vertical force of the chains.
The weight of the light is,
[tex]\begin{gathered} W=4F_v \\ =4\times36.9 \\ =147.6\text{ N} \end{gathered}[/tex]The mass of the light is,
[tex]\begin{gathered} m=\frac{W}{g} \\ =\frac{147.6}{10} \\ =14.76\text{ kg} \end{gathered}[/tex]Hence, the mass of the light is 14.76 kg.