Find the missing side lengths using trig ratios.61010у y29°BX ХVyaTo find the perimeter, you add all the side lengths. So, the perimeter of this triangle is

x=8.746, y=4.848 and 2P=23.594
1) Since we have the angles and the hypotenuse, we can find the missing legs by applying the following trigonometric ratios:
[tex]\begin{gathered} y=\sin (B) \\ y=\frac{opposite\text{ leg}}{\text{hypotenuse}} \\ y=\text{ sin(}29) \\ \frac{y}{10}=\sin (29) \\ y=10\cdot\sin (29) \\ y\approx4.848 \end{gathered}[/tex]2) For the missing leg x, we can write out in terms of the cosine (29) or sine (61)
[tex]\begin{gathered} \cos (29)=\frac{x}{10} \\ x=10\cdot\cos (29) \\ x\approx8.746 \end{gathered}[/tex]3) And finally, the Perimeter (2P) is equal to:
2P = 4.848 +8.746+10
2P=23.594
Rounding off to the nearest thousandth.