Find the missing side lengths using trig ratios.61010у y29°BX ХVyaTo find the perimeter, you add all the side lengths. So, the perimeter of this triangle is

Find the missing side lengths using trig ratios61010у y29BX ХVyaTo find the perimeter you add all the side lengths So the perimeter of this triangle is class=

Respuesta :

x=8.746, y=4.848 and 2P=23.594

1) Since we have the angles and the hypotenuse, we can find the missing legs by applying the following trigonometric ratios:

[tex]\begin{gathered} y=\sin (B) \\ y=\frac{opposite\text{ leg}}{\text{hypotenuse}} \\ y=\text{ sin(}29) \\ \frac{y}{10}=\sin (29) \\ y=10\cdot\sin (29) \\ y\approx4.848 \end{gathered}[/tex]

2) For the missing leg x, we can write out in terms of the cosine (29) or sine (61)

[tex]\begin{gathered} \cos (29)=\frac{x}{10} \\ x=10\cdot\cos (29) \\ x\approx8.746 \end{gathered}[/tex]

3) And finally, the Perimeter (2P) is equal to:

2P = 4.848 +8.746+10

2P=23.594

Rounding off to the nearest thousandth.

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