Question

what is the dimensions of the entire figure on an area of 132 square inches?

Answer 1

Let the length of the given figure is: L=8+x

And the width is: W= 3+x

As it isa square:

So:

$\begin{gathered} (8+x)(3+x)=132 \\ 24+8x+3x+x^2=132 \\ x^2+11x+24-132=0 \\ x^2+11x-108=0 \end{gathered}$