If ABCD is dilated by a factor of 3, thecoordinate of C' would be:6ол5С43B2. 1-6 -5 4-3 -2 -1 012 345-1NOADC' = ([?], [ 12.3

From the question provided, if every coordinate on the quadrilateral is dilated by a factor of 1/2, then the coordinates of every point would be multiplied by 1/2.
Therefore, using the factor of 1/2 to dilate, the coordinates of pont C would be;
[tex]\begin{gathered} C=(2,4) \\ \text{Dilated by }\frac{1}{2}; \\ C^{\prime}=(2\times\frac{1}{2},4\times\frac{1}{2}) \\ C^{\prime}=(1,2) \end{gathered}[/tex]ANSWER:
The coordinates of C' would therefore be;
[tex]C^{\prime}(1,2)[/tex]