one number is thirteen less than another.if their sum is increased by awven, the result is 90.find the numbers. )enter your answers as a comma-aeperated list)

Given:
One number is thirteen less than another number.
If the sum is increased by seven, the result is 90.
Required:
We need to find the unknown numbers.
Explanation:
Let a be the second number.
The first number is 13 less than a.
The first number is a-13.
The sum of the number is
[tex]a+a-13[/tex]Their sum is creased by 7, then its result is 90.
[tex]a+a-13+7=90[/tex][tex]2a-6=90[/tex]Add 6 to both sides of the equation.
[tex]2a-6+6=90+6[/tex][tex]2a=96[/tex]Divide both sides by 2.
[tex]\frac{2a}{2}=\frac{96}{2}[/tex][tex]a=48[/tex]The second number is 48.
Subtract 13 from 48 to find the first number.
[tex]48-13=35[/tex]The first number is 35.
Final answer:
[tex]35,48[/tex]