Given the expression:
[tex]\frac{\tan(\frac{-2\pi}{3})}{\sin(\frac{7\pi}{4})}-\sec (-\pi)\text{ =}[/tex][tex]\frac{\sqrt[]{3}}{\frac{-\sqrt[]{2}}{2}}-(-1)\text{ =}[/tex][tex]-\frac{\sqrt[]{3}}{\frac{\sqrt[]{2}}{2}}+1\text{ =}[/tex][tex]-\frac{2\sqrt[]{3}}{\sqrt[]{2}}+1=[/tex][tex]-\sqrt[]{6}+1[/tex]
