Question

DEPENDENT EVENTS AND CONDITIONAL PROBABILITY There are 43 milk jugs in a refrigerator with 11 jugs being spoiled. If you randomly choose 5 jugs, what is the probability that the first 2 are good and the last 3 are spoiled? Give your answer as an exact fraction and reduce the fraction as much as possible.

Answer 1

43 milk jugs and 11 jugs spoiled

Sample = 54

Equation n! / ( n - k)!

a) 43! / (43 - 2)! * 11! / (11 - 3)!

1806 990

54! = 2.3 x 10^7

2796/ 2.3x 10^7 = 0.00012

Probability = 0.00012

or

Probability = 12/100000 = 3/25000