Respuesta :

First we make x-3=0 and solve for x, that is x=3. Then we write the polynomial with all the monomials (including those that have null coefficient)

[tex]x^4-5x^3+0x^2+17x+3[/tex]

and we take over the coefficients, 1, -5, 0, 17, 3. So we start with our method

Now, we take all the new coefficient and low the grade of the polynomial, the new coefficients are 1, -2, -6, -1, 0, so

[tex]1x^3-2x^2-6x-1+\frac{0}{x-3}[/tex]

Since the remainder is zero, we can take it off, so x^4-5x^3+17x+3 divided by x-3 is equal to

[tex]x^3-2x^2-6x-1[/tex]

Ver imagen WilloughbyE763077
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