Since we have been given the balanced reaction, we can just follow the stoichimetry of the reaction to calculate it.
By the stoichimetry, 1 mol of MnO₂ reacts with 4 moles of HCl. using Rule of three, we have:
1 mol MnO₂ --- 4 mol HCl
4.50 mol MnO₂ --- x
[tex]\begin{gathered} \frac{1mol}{4.50mol}=\frac{4mol}{x} \\ x=(\frac{4.50\cdot4}{1})mol \\ x=18mol \end{gathered}[/tex]So, 18 moles of HCl will react with 4.5 moles od MnO₂ (assuming complete reaction).