Respuesta :

Since we have been given the balanced reaction, we can just follow the stoichimetry of the reaction to calculate it.

By the stoichimetry, 1 mol of MnO₂ reacts with 4 moles of HCl. using Rule of three, we have:

1 mol MnO₂ --- 4 mol HCl

4.50 mol MnO₂ --- x

[tex]\begin{gathered} \frac{1mol}{4.50mol}=\frac{4mol}{x} \\ x=(\frac{4.50\cdot4}{1})mol \\ x=18mol \end{gathered}[/tex]

So, 18 moles of HCl will react with 4.5 moles od MnO₂ (assuming complete reaction).

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