Question

can you please send me the

Answer 1

we have the expression

$\frac{106+15i}{-8+3i}$

step 1

Multiplicate numerator and denominator by the conjugate of denominator

so

$\frac{106+15i}{-8+3i}\cdot\frac{-8-3i}{-8-31}$

Remember that

i^2=-1

so

$\frac{106+15i}{-8+3i}\cdot\frac{-8-3i}{-8-31}=\frac{-848-318i-120i-45i^2}{64-9i^2}$$\begin{gathered} \frac{-848-318i-120i-45i^2}{64-9i^2}=\frac{-848-438i+45}{64+9} \\ \\ =\frac{-438i-803}{73} \end{gathered}$

Simplify

$\frac{-438i-803}{73}=\frac{-438i}{73}-\frac{803}{73}=-6i-11$

the answer is

-6i-11