Question

let g(x) = 3x+2 and f(x)= (x-2)/3. Find the value. f(g(0))a) 0b) -2/3c) 1d) -1

Answer 1

We have two functions:

$\begin{gathered} g\mleft(x\mright)=3x+2 \\ f\mleft(x\mright)=\frac{x-2}{3} \end{gathered}$

We have to calculate f(g(0)).

We can do it like this:

$\begin{gathered} f(g(0))=\frac{g(0)-2}{3} \\ f(g(0))=\frac{\lbrack3(0)+2\rbrack-2}{3} \\ f(g(0))=\frac{0+2-2}{3} \\ f(g(0))=\frac{0}{3} \\ f(g(0))=0 \end{gathered}$

Answer: a) 0