Question

-Quadratic Equations-Determine the number and nature of the solutions to each equation; then find the solution.

Answer 1

Given the quadratic equation:

$x^2+14x+49=0$

By factoring the equation:

$\begin{gathered} (x+7)(x+7)=0 \\ (x+7)^2=0 \end{gathered}$

so, the number of solutions = 1 (real solution)

We will find the value of x:

$\begin{gathered} x+7=0 \\ x=-7 \end{gathered}$