start by making a sketch of the basketball court giving the width the value of x, and the length will be twice the with (2x) and 6 meters longer (2x+6)
using the definition of the perimeter and the value of the perimeter write an equation and solve for x
[tex]2\cdot(x+(2x+6))=96[/tex]solve the equation
[tex]\begin{gathered} 2\cdot(3x+6)=96 \\ 6x+12=96 \\ 6x=96-12 \\ 6x=84 \\ x=\frac{84}{6} \\ x=14 \end{gathered}[/tex]the width of the basketball court is 14 meters.
using this value find the length
[tex]\begin{gathered} l=2x+6 \\ l=2(14)+6 \\ l=28+6 \\ l=34m \end{gathered}[/tex]the lenght of the basketball court is 34 meters.
Check if your answer is correct
[tex]\begin{gathered} 2w+2l=P \\ 2(x)+2(2x+6)=96 \\ 28+68=96 \\ 96=96 \end{gathered}[/tex]
