Question

2/3 + 3k/4 = 71/12. How do I do this?

Answer 1

We want to solve the following equation:

$\frac{2}{3}\text{ + }\frac{3k}{4}\text{ = }\frac{71}{12}$

that is equivalent to :

$\frac{2}{3}-\frac{2}{3}\text{ + }\frac{3k}{4}\text{ = }\frac{71}{12}\text{ - }\frac{2}{3}$

that is

$\text{ }\frac{3k}{4}\text{ = }\frac{71}{12}\text{ - }\frac{2}{3}$

now, we will solve the right part of the equation:

$\text{ }\frac{3k}{4}\text{ = }\frac{71}{12}\text{ - }\frac{2x4}{3x4}\text{ = }\frac{71}{12}\text{ - }\frac{8}{12}\text{ = }\frac{71-8}{12}\text{ = }\frac{63}{12}$

that is :

$\text{ }\frac{3k}{4}\text{ = }\frac{63}{12}$

Now, we resolve for k:

$\text{ k = }\frac{63\text{ x 4}}{12\text{ x 3}}\text{ = }\frac{252}{36}\text{ = 7}$

we can conclude that :

k = 7