We want to do the following sum
[tex]4\frac{3}{8}-2\frac{1}{6}+3\frac{5}{12}[/tex]To do it, we can sum all the integer values and after looking at the fractions and do the adjustments, first, sum the integer values:
[tex]\begin{gathered} 4-2+3=5 \\ \end{gathered}[/tex]Now, let's look at the fractions
[tex]\frac{3}{8}-\frac{1}{6}+\frac{5}{12}[/tex]I'll do the subtraction first, then
[tex]\frac{3}{8}-\frac{1}{6}=\frac{3\cdot6-8}{8\cdot6}=\frac{18-8}{48}=\frac{10}{48}=\frac{5}{24}[/tex]And now we do the sum
[tex]\frac{5}{24}+\frac{5}{12}=\frac{5}{24}+\frac{10}{24}=\frac{5+10}{24}=\frac{15}{24}=\frac{5}{8}[/tex]Then, the final answer is represented by the integer value and the fraction
[tex]4\frac{3}{8}-2\frac{1}{6}+3\frac{5}{12}=5\frac{5}{8}[/tex]Final answer:
[tex]\begin{equation*} 5\frac{5}{8} \end{equation*}[/tex]