Given:
• Each Charge = 60.0 nC
,
• Force between the charges = 4 N
Let's find the center-to-center distance between thw two point charges.
To find the center-to-center distance, apply the formula:
[tex]F=\frac{kQ_1Q_2_{}}{r^2}[/tex]
Where:
Q1 = Q2 = 60.0 nC
k is the Coulomb's constant = 9 x 10⁹ N⋅m^2⋅C^-2
r is the distance
F is the force = 4 N
Rewrite the formula for r, input the values and solve for r.
We have:
[tex]\begin{gathered} r=\sqrt[]{\frac{kQ_1Q_2}{F}} \\ \\ r=\sqrt{\frac{9\times10^9\times(60\times10^{-9})\times(60\times10^{-9})}{4}} \\ \\ r=\sqrt[]{8.1\times10^{-6}} \\ \\ r=2.8\times10^{-3}\text{ m }\approx2.8mm \end{gathered}[/tex]
Therefore, the center-to-center distance is 2.8 mm
ANSWER:
2.8 mm
