Question

A water container at training is full and holds 5 liters of water . juan emptied 1 3/8 liters of the water into his drink bottle .crystal emptied 2 1/5 liters into her drink bottle after jose emptied some of water into his drink bottle there where 5/6 liters left in the original container. how much water did jose take?

Answer 1

Given:

Total amount of water = 5 liters

Amount used by Juan = 1⅜ liters

Amount used by Crystal = 2⅕ liters

Remaining amount of water = ⅚ liters

To find the amount of water used by Jose, use the formula:

Total Amount of water = Amount used by Juan + Amount used by Crystal + Amount used by Jose + remainder

Amount used by Jose = Total amount - (Amount used by Juan + Amount used by crystal + remainder)

Thus, we have:

$\text{ Amount used by Jose = }5\text{ - (1}\frac{3}{8}+2\frac{1}{5}+\frac{5}{6})$

Solving further:

$\begin{gathered} Amount\text{ used by Jose = 5 - (}\frac{11}{8}+\frac{11}{5}+\frac{5}{6}) \\ \\ \end{gathered}$$\begin{gathered} \text{Amount used by Jose = }5\text{ - (}\frac{165+264+100}{120}) \\ \\ \text{Amount used by Jose = 5 - (}\frac{529}{120}) \\ \\ \end{gathered}$$\begin{gathered} \text{Amount used by Jose = }\frac{5}{1}-\frac{529}{120}=\frac{600-529}{120}=\frac{71}{120} \\ \\ \end{gathered}$

ANSWER:

$\frac{71}{120}\text{ Liters}$

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