Question

Consider the following equation of a circle what is the circle's center?

Answer 1

Recall that the radius-center form of the equation of a circle is as follows:

$(x-h)^2+(y-k)^2=r^2,$

where (h,k) is the circle's center, and r is its radius.

Therefore the center of the circle that represents the given equation is:

$(1,\frac{2}{9}).$

Answer:

$(1,\frac{2}{9}).$