Question

Directions: Solve each equation. Check your solution(s) then indicate whether or not the solutions are extraneous.

Answer 1

we have

Part 3

$3\mleft|x-2\mright|=18$

step 1

Divide by 3 both sides

$|x-2|=6$

Solve the first case (positive)

$\begin{gathered} +(x-2)=6 \\ x=6+2 \\ x=8 \end{gathered}$

Solve the second case (negative)

$\begin{gathered} -(x-2)=6 \\ x-2=-6 \\ x=-6+2 \\ x=-4 \end{gathered}$