Question

solve the following quadratic equationslelect the correct answer

Answer 1

We have

$\begin{gathered} (x+4)^2=25 \\ (x+4)^2-25=0 \end{gathered}$

To find the roots of the equation (x+4)^2 must be equal to 25

$\begin{gathered} (x+4)^2=25 \\ x+4=\sqrt[]{25} \\ x=\pm5-4 \\ x=-9\text{ and }x=1 \end{gathered}$

So, the answer is letter C. x = -9 and x = 1.