ANSWER
[tex]14V[/tex]EXPLANATION
We want to find the voltage of the battery.
To do this, we apply the relationship between voltage and current using Ohm's law:
[tex]V=IR[/tex]where R = resistance
I = current
The resistance is the total resistance of the circuit. Since the resistors are in parallel, the total resistance is found by using:
[tex]\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}[/tex]Therefore, we have that:
[tex]\begin{gathered} \frac{1}{R}=\frac{1}{4}+\frac{1}{10}=\frac{5+2}{20}=\frac{7}{20} \\ \Rightarrow R=\frac{20}{7}\Omega \end{gathered}[/tex]Therefore, the voltage of the battery is:
[tex]\begin{gathered} V=4.9\cdot\frac{20}{7} \\ V=14V \end{gathered}[/tex]The voltage of the battery is 14V.