Notice that for this question, they are providing you with:
1) The slope of the line (4)
2) a point on the plane through which the line goes (6, -2)
So you can directly use for this the "point-slope" form of a line which is as follows:
[tex]y-y_0=m(x-x_{0)}[/tex]This includes m as the slope, and the pair (x0, y0) as the pair representing the point the line goes through.
So, let's use the info they gave you to complete this:
[tex]y-(-2)=4(x-6)[/tex]which we can work out a little more:
[tex]y+2=4x-24[/tex]And even a little more to finish the equation of the line in its standard slope-intercept form:
[tex]y=4x-24-2=4x-26[/tex]So the equation of the line is:
[tex]y=4x-26[/tex]