Question

Tyrell was late for class 3 times in the month of June . Each time he was late he missed 5 and 1/2 minutes of class time . What is the total amount of class time Tyrell missed in the month of June ? A. 8 and 1/2 B . 15 minutes C . 16 and 1/2

Answer 1

Tyrell was late 3 times, each time he was late for 5 1/2 minutes, to determine how much time he missed in June, you have to multiply 5 1/2 by 3

$5\frac{1}{2}\cdot3$

First, express the mixed number as a fraction:

-Divide the whole number by 1 and add 1/2

$5\frac{1}{2}=\frac{5}{1}+\frac{1}{2}$

-Multiply the first fraction by 2, to express it as its equivalent with denominator 2, and add both fractions:

$\frac{5\cdot2}{1\cdot2}+\frac{1}{2}=\frac{10}{2}+\frac{1}{2}=\frac{10+1}{2}=\frac{11}{2}$

Multiply the result by 3

$\frac{11}{2}\cdot3=\frac{11}{2}\cdot\frac{3}{1}=\frac{11\cdot3}{2}=\frac{33}{2}$

Express the result as a mixed fraction:

Divide 33 by 2:

$33\div2=16.2$

The whole number of the result is 16 and there are 0.5 remainings.

0.5 expressed as a fraction is 1/2.

So Tyrell missed 16 and 1/2 minutes in the month of June