We can represent the sum of the three consecutive integers as:
[tex]n+(n+1)+(n+2)=177[/tex]Then, we need to solve the equation for n, then:
[tex]3n+3=177_{}\Rightarrow3n=177-3\Rightarrow3n=174\Rightarrow n=\frac{174}{3}\Rightarrow n=58[/tex]Then, the largest of the integers is n + 2 or 58 +2 = 60.
The reason is that the other integers are 58, 58 + 1 = 59, that is, 58 and 59.
We can check that:
58 + 59 + 60 = 177.