Question

A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8 m/s at a -47.0° angle. Whatis the x-component of the ball'sfinal velocity?X-component (m/s)

Answer 1

According to the problem, the final velocity module is 14.8 m/s and its direction is -47°. To find the x-component, we have to use the following formula

$v_x=v\cdot\cos \theta$

Using the given information, we have

$\begin{gathered} v_x=14.8m/s\cdot\cos (-47) \\ v_x\approx10.1m/s \end{gathered}$

Hence, the x-component is 10.1 m/s, approximately.