1 2 11 -1 iyim -3 1 1 1 1 1 1 O A. y=x2 + 3x – 2 O B. y+2 = - 2(x+3)2 O c. v+2 = 2(x+3) O d. v= (x+4)(x+2)

Answer:
c. y + 2 = 2(x + 3)²
Explanation:
When we replace (x, y) equal to (-4,0), (-2, 0) and (-3, -2) on the correct equation, the equation is satisfy.
So, for option c, we get:
if (x, y) = (-4, 0)
y + 2 = 2(x + 3)²
0 + 2 = 2(-4 + 3)²
2 = 2(-1)²
2 = 2
If (x, y) = (-2, 0)
y + 2 = 2(x + 3)²
0 + 2 = 2(-2 + 3)²
2 = 2(1)²
2 = 2
If (x, y) = (-3, -2)
y + 2 = 2(x + 3)²
-2 + 2 = 2(-3 + 3)²
0 = 2(0)²
0 = 0
Since option c. y + 2 = 2(x + 3)² is satisfied in all points, the answer is c.