To answer this question we will use the following property:
[tex](a^7)^{\frac{1}{7}}=a.[/tex]
Subtracting 8 to the equation obtained on a) we get:
[tex]\begin{gathered} y-8=x^7(7)+8-8, \\ y-8=x^7(7). \end{gathered}[/tex]
Dividing the above result by 7 we get:
[tex]\begin{gathered} \frac{y-8}{7}=\frac{x^7(7)}{7}, \\ \frac{y-8}{7}=x^7. \end{gathered}[/tex]
Taking the above result to the power of 1/7 we get:
[tex](\frac{y-8}{7})^{\frac{1}{7}}=(x^7)^{\frac{1}{7}}.[/tex]
Using the first property we get:
[tex]x=(\frac{y-8}{7})^{\frac{1}{7}}.[/tex]
Answer: x=g(y)= ((y-8)/7)^(1/7).is
