Graph triangle ABC with vertices A(0,5) B(4,3) and C(2,-1) and it’s image after a reflection in the line y=2I starting by graphing triangle ABC just so you know!

Given the triangle ABC, you can identify that the coordinates of its vertices are:
[tex]\begin{gathered} A\mleft(0,5\mright) \\ B\mleft(4,3\mright) \\ C\mleft(2,-1\mright) \end{gathered}[/tex]You know that it is reflected over the following line:
[tex]y=2[/tex]Notice that it has the form of a horizontal line. It intersects the y-axis at this point:
[tex](0,2)[/tex]Knowing that you can graph the line. See the picture below:
By definition, when a figure is reflected over a line, the points of the Image (the figure obtained after the transformation) and the points of the Pre-Image (the original figure), have the same distance from the line of reflection.
Notice that:
- Point A is 3 units away from the line of reflection.
- Point B is 1 unit away from the line.
- Point C is 3 units away from the line.
See the picture attached:T
Therefore, the points of the Image will have this distance from the line of reflection:
- Point A' will be 3 units away from the line of reflection.
- Point B' will be 1 unit away from the line.
- Point C' will be 3 units away from the line.