Question

A rectangular field has a length that is triple its width and a diagonal of 98 meter find the areaI need help, help me please

Answer 1

Data:

l = 3w

d = 98

To find the area, lets start drawing the field:

The area of rectangle is

$A=b\cdot h$

In this case

b = w

h= l = 3w

To determine the value of w, we can use the right triangle and the value of the diagonal that is the hypotenuse of the triangle. Then using Pythagoras theorem:

$w^2=d^2-(3w)^2$

We can clear the w from this equation:

$w^2=d^2-9w^2$$w^2+9w^2=98^2$$10w^2=98^2$$w^2=\frac{98^2}{10}$$w=\sqrt[]{\frac{98^2}{10}}=\sqrt[]{960.4}=30.99\approx40$

Now we know the value of w = 40

Then the area of the field is:$A=w\cdot3w$$A=40m\cdot3(40m)=4800m^2$