Question

What is the acceleration of the object at t = 2.5 s? (Indicate the direction with the sign of your answer.)________m/s^2

Answer 1

ANSWER

$\begin{equation*} -2.4\text{ m/s}^2 \end{equation*}$

EXPLANATION

To find the acceleration of the object at that time, we have to divide its velocity by the time:

$a=\frac{v}{t}$

The velocity of the object at t = 2.5s is 6 m/s. Therefore, the value of the object's acceleration at t = 2.5 s is:

$\begin{gathered} a=\frac{6}{2.5} \\ \\ a=2.4\text{ m/s}^2 \end{gathered}$

Notice from the graph that the velocity of the object is reducing in that time interval. This means that its acceleration has a negative value (deceleration).

Hence, the acceleration of the object at that time is:

$a=-2.4\text{ m/s}^2$