Given:
4 types of crust
6 types of toppings
7 kinds of cheese
Find the number of different mega calzones that can be made with 3 different toppings and 2 different kinds of cheese.
Solution:
In choosing a crust, there are only 4 ways to choose since there are only 4 options.
In choosing 3 different toppings out of 6, we can use the combination formula since the order doesn't matter. The formula is:
[tex]nCr=\frac{n!}{r!(n-r)!}[/tex]in which n = 6 and r = 3.
[tex]_6C_3=\frac{6!}{3!(6-3)!}[/tex][tex]_6C_3=\frac{6!}{3!(3!)}[/tex][tex]_6C_3=\frac{6\times5\times4}{3\times2}=\frac{120}{6}=20[/tex]Hence, there are 20 different combinations of three toppings we can form out of 6 available toppings.
Lastly, in choosing 2 kinds of cheese out of 7, we can still use the combination formula in which n = 7 and r = 2.
[tex]_7C_2=\frac{7!}{2!(7-2)!}[/tex][tex]_7C_2=\frac{7!}{2!(5)!}[/tex][tex]_7C_2=\frac{7\times6}{2\times1}=\frac{42}{2}=21[/tex]Hence, there are 21 combinations of 2 kinds of cheese from the 7 available types of cheese.
So, the number of different mega calzones that can be made with 3 different toppings and 2 different kinds of cheese is:
[tex]4crust\times20toppings\times21cheese=1,680[/tex]There are 1, 680 different mega calzones that can be made with 3 different toppings and 2 different kinds of cheese.