Question

solve the following system of equation using the substitution method y=3x-14 ... (1)y=x-10 ... (2)

Answer 1

We have the next equations

y=3x-14 ... (1)

y=x-10 ... (2)

we will substitute the value of y of the first equation into the second equation

$3x-14=x-10$

we sum the terms with x and the terms without x

$\begin{gathered} 3x-x=-10+14 \\ 2x=4 \\ x=\frac{4}{2} \\ x=2 \end{gathered}$

then we substitute the value of x in the first equation

$\begin{gathered} y=3x-14=3(2)-14 \\ y=-8 \end{gathered}$

the solution of the system of equations is

x=2 , y=-8