the compound interest formula is
[tex]\begin{gathered} I=P(1+\frac{r}{n})^{n\cdot t} \\ \end{gathered}[/tex]where P is the principal, r the rate, n the compounding frequency, t the time and I the interest.
In this case,
[tex]\begin{gathered} P=500 \\ r=0.11 \\ t=2\text{ (years)} \\ n=1\text{ (compoud annually)} \end{gathered}[/tex]by substituying those values into the formula, we have
[tex]\begin{gathered} I=(500)(1+\frac{0.11}{1})^{1\cdot2} \\ I=500(1.11)^2 \\ I=500(1.2321) \\ I=616.05 \end{gathered}[/tex]Therefore, in 2 years, Miguel will have 616.05 dollars.