Answer:
[tex](-\infty,-\frac{4}{3})\cup(-\frac{4}{3},\infty)[/tex]Explanation:
Given f(x) defined below:
[tex]f\mleft(x\mright)=\frac{2}{3x+4}[/tex]The domain of f(x) is the set of the values of x for which f(x) is defined.
Find the excluded values, the values at which f(x) is undefined. To do this, set the denominator equal to 0 and solve for x.
[tex]\begin{gathered} 3x+4=0 \\ 3x=-4 \\ x=-\frac{4}{3} \end{gathered}[/tex]The excluded value of the domain is -4/3.
Therefore, the domain of f(x) is:
[tex](-\infty,-\frac{4}{3})\cup(-\frac{4}{3},\infty)[/tex]