Respuesta :

Given the equation of hyperbola :

[tex]25x^2-4y^2=100[/tex]

Divide both sides by 100:

[tex]\begin{gathered} \frac{25x^2}{100}-\frac{4y^2}{100}=1 \\ \\ \frac{x^2}{4}-\frac{y^2}{25}=1 \\ \\ \frac{x^2}{2^2}-\frac{y^2}{5^2}=1 \end{gathered}[/tex]

So, the center of the hyperbola = (0,0)

The vertices will be : (2, 0) and (-2,0)

The line of symmetry : y = 0

The intercepts are (2,0) and (-2,0) which represents x- intercepts

There is no y - intercepts for the given hyperbola

The domain will be : all real numbers except (-2 , 2 )

The graph of the hyperbola will be as following :

Ver imagen MadalyneO618976
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