It is given that
[tex]a=6.3,b=9.3,c=8.3[/tex]Use the cosine rule to get:
[tex]\begin{gathered} \cos A=\frac{b^2+c^2-a^2}{2bc}=\frac{(9.3)^2+(8.3)^2-(6.3)^2}{2\ast9.3\ast8.3}=0.7493 \\ A=\cos ^{-1}(0.7493)=41.46\approx41.5^{\circ} \end{gathered}[/tex]Similarly for angle B it follows:
[tex]\begin{gathered} \cos B=\frac{a^2+c^2-b^2}{2ac}=\frac{(6.3)^2+(8.3)^2-(9.3)^2}{2\ast6.3\ast8.3}=\frac{2209}{10458} \\ B=\cos ^{-1}(\frac{2209}{10458})=77.8^{\circ} \end{gathered}[/tex]The value for angle C is given by the formula
[tex]\begin{gathered} A+B+C=180 \\ C=180-B-A \\ C=180-77.8-41.5=60.7^{\circ} \end{gathered}[/tex]Hence option C is correct.