Question

Solve the system using the method of elimination by addition

Answer 1

Given:

There are given the two systems of the equation:

$\begin{gathered} \frac{3}{5}x+\frac{2}{3}y=1...(1) \\ 18x+20y=30...(2) \end{gathered}$

Explanation:

According to the question:

We need to solve the equation by using the elimination method.

So,

To solve the above equation, we need to perform the elimination method.

So,

$\begin{gathered} 18(\frac{3}{5}x+\frac{2}{3}y=1)=(\frac{54}{5}x+12y=18)...(3) \\ \frac{3}{5}(18x+20y=30)=(\frac{54}{5}x+12y=18)...(4) \end{gathered}$

Then,

We need to subtract equation (3) from equation(4):

Then,

$\begin{gathered} (\frac{54}{5}x+12y=18)-(\frac{54}{5}x+12y=18) \\ 0 \end{gathered}$

Final answer:

Hence, the solution is 0.