The given function is f(x) = 8x^2 + 3x - 3.
a.
[tex]\begin{gathered} f(x+1)=8(x+1)^2+3(x+1)-3 \\ =8(x^2+2x+1)+3x+3-3 \\ =8x^2+16x+8+3x \\ =8x^2+19x+8 \end{gathered}[/tex]b.
[tex]\begin{gathered} f(-x)=8(-x)^2+3(-x)-3 \\ =8x^2-3x-3 \end{gathered}[/tex]