[tex]s\:=12000\left(\frac{\left(\left(1+\frac{0.06}{2}\right)^{16}-1\right)}{\frac{0.06}{2}}\right)\:[/tex][tex]\frac{\left(1+\frac{0.06}{2}\right)^{16}-1}{\frac{0.06}{2}}=\frac{\left(\left(1+\frac{0.06}{2}\right)^{16}-1\right)\cdot\:2}{0.06}[/tex][tex]\left(1+\frac{0.06}{2}\right)^{16}=\text{ }(\frac{1\cdot\:2}{2}+\frac{0.06}{2})^{16}=\left(\frac{2.06}{2}\right)^{16}=\frac{105166.04119}{65536}[/tex][tex]s=12000\cdot\frac{2\cdot\frac{39630.04119}{65536}}{0.06}[/tex][tex]s=\frac{951120988.62667}{3932.16}\quad\left(\mathrm{Decimal}:\quad s=241882.57563\right)[/tex]
The "intermediate values" in this question means that when performing all calculation you should not round any values of the intermediate steps.
The answer is s=241882.57563 = 241883
