Question:
Solution:
The given figure is composed of the following figures:
1) two lower triangles and a square.
2) An upper triangle. (the biggest)
Therefore, the area of the given figure is the sum of the figures that compose it. Now, from now on, let us denote the height by h and the base by b.
Lower triangles:
Area of the lower-left triangle:
[tex]ALT\text{ =}\frac{b\text{ x h}}{2}\text{ = }\frac{(2)(2)}{2}=\text{ 2}[/tex]Area of the lower-right triangle:
[tex]ART\text{ =}\frac{b\text{ x h}}{2}\text{ = }\frac{(5)(2)}{2}=5[/tex]Area of the lower square:
[tex]AS\text{ = bxh = (2)(2) = 4}[/tex]Upper triangle:
Area of the upper triangle:
[tex]AUT\text{ =}\frac{b\text{ x h}}{2}\text{ = }\frac{(9)(3.5)}{2}=15.75[/tex]Thus, we can conclude that the total area of the shape shown is:
[tex]A\text{ = ALT + ART + AS+ AUT }[/tex]that is:
[tex]A\text{ =}2+5+4+15.75\text{ = 26.75}[/tex]