Question

please help me ASAP!!!

Answer 1

$\begin{gathered} f(x)=2x^3+6 \\ y=2x^3+6 \\ y-6=2x^3 \\ \frac{y-6}{2}=x^3 \\ x=\sqrt[3]{\frac{y-6}{2}} \\ f^{-1}(x)\text{ =}\sqrt[3]{\frac{x-6}{2}} \end{gathered}$