SOLUTION
We want to solve for x in
[tex]-2x+3b>5[/tex]This becomes
[tex]\begin{gathered} -2x+3b>5 \\ -2x>5-3b \\ \text{divide both sides by -2, and the inequality reverses, we have } \\ \frac{-2x}{-2}<\frac{5-3b}{-2} \\ x<\frac{5-3b}{-2} \end{gathered}[/tex]Hence the answer is
[tex]x<\frac{5-3b}{-2}[/tex]