Question

Factor the binomial or identify it as prime. 2z^4 - 2

Answer 1

The given binomial expression is:

$2z^4-2$

The common factor is 2.

Hence, we factor out 2

$2z^4-2=2(z^4-1)$

We then apply the diference of

Therefore, the factored answer is

$\begin{gathered} 2(z^4-1) \\ =2(z^2-1)(z^2+1) \\ =2(z-1)(z+1)(z^2+1) \end{gathered}$