Derivate the equation:
[tex]\frac{d}{dt}\left(12t-1.86t^2\right)[/tex][tex]=\frac{d}{dt}\left(12t\right)-\frac{d}{dt}\left(1.86t^2\right)[/tex][tex]=12-3.72t[/tex]Now replace the numbers of the intervals:
1:
8.28
2:
4.56
Find the average:
[tex]\frac{8.28+4.56}{2}=6.42\text{ m/s}[/tex]