We are asked to find the volume of the given sphere.
Recall that the volume of a sphere is given by
[tex]V=\frac{4}{3}\cdot\pi\cdot r^3[/tex]Where π is a constant and r is the radius of the sphere.
Also, recall that the radius is half of the diameter.
[tex]r=\frac{D}{2}[/tex]For the given problem, the diameter of the sphere is 2 in
[tex]\begin{gathered} V=\frac{4}{3}\cdot\pi\cdot r^3 \\ V=\frac{4}{3}\cdot\pi\cdot(\frac{D}{2})^3 \\ V=\frac{4}{3}\cdot3.14\cdot(\frac{2}{2})^3 \\ V=\frac{4}{3}\cdot3.14\cdot(1)^3 \\ V=\frac{4}{3}\cdot3.14\cdot1 \\ V=4.1867 \\ V=4.19\: in^3\quad (\text{rounded to nearest hundredth)} \end{gathered}[/tex]Therefore, the volume of the given sphere is 4.19 cubic inches.