Robin tosses a pair of 6-sided dice. The odds in favor of the sum of the 2 dice rolls being greater than 8 are 5:13.What is the probability that the sum of the 2 dice rolls will not be greater than 8?

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Answer:

The probablity that the sum of the 2 dice rolls will not be greater than 8 = 8/13

Explanation:

The probablity that the sum of the 2 dice rolls being greater than 8 = 5/13

P(sum > 8) = 5/13

(The probablity that the sum of the 2 dice rolls being greater than 8) + (The probablity that the sum of the 2 dice rolls will not be greater than 8) = 1

P(Sum > 8) + P(Sum ≤ 8) = 1

P(sum ≤ 8) = 1 - P(sum > 8)

P(sum ≤ 8) = 1 - 5/13

P(sum ≤ 8) = 8/13

The probablity that the sum of the 2 dice rolls will not be greater than 8 = 8/13

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